(28x^2-3x+1)/(4x+3)

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Solution for (28x^2-3x+1)/(4x+3) equation: 


D( x )

4*x+3 = 0

4*x+3 = 0

4*x+3 = 0

4*x+3 = 0 // - 3

4*x = -3 // : 4

x = -3/4

x in (-oo:-3/4) U (-3/4:+oo)

(28*x^2-(3*x)+1)/(4*x+3) = 0

(28*x^2-3*x+1)/(4*x+3) = 0

28*x^2-3*x+1 = 0

28*x^2-3*x+1 = 0

DELTA = (-3)^2-(1*4*28)

DELTA = -103

DELTA < 0

1 = 0

1/(4*x+3) = 0

x belongs to the empty set

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